The wall of a room is made of plywood that has a thickness of 3.00 cm and an area of 18.0 m?. The room temperature is maintained at 25.0 °C higher than outside temperature. Ignore other heat loss mechanisms except by conduction. Given that: Thermal conductivity of plywood, kpływood = 0.0800 W m¯1 °C-' (a) Find the magnitude of the rate of heat loss through the wall. (b) culate the amount of heat loss through the wall in half a day.
The wall of a room is made of plywood that has a thickness of 3.00 cm and an area of 18.0 m?. The room temperature is maintained at 25.0 °C higher than outside temperature. Ignore other heat loss mechanisms except by conduction. Given that: Thermal conductivity of plywood, kpływood = 0.0800 W m¯1 °C-' (a) Find the magnitude of the rate of heat loss through the wall. (b) culate the amount of heat loss through the wall in half a day.
Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter2: Steady Heat Conduction
Section: Chapter Questions
Problem 2.63P
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![The wall of a room is made of plywood that has a thickness of 3.00 cm and an area of
18.0 m?. The room temperature is maintained at 25.0 °C higher than outside
temperature. Ignore other heat loss mechanisms except by conduction.
Given that:
Thermal conductivity of plywood, kpływood = 0.0800 W m¯1 °C-'
(a)
Find the magnitude of the rate of heat loss through the wall.
(b)
Calculate the amount of heat loss through the wall in half a day.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbbc4904b-07f7-4140-90cd-31ab5db47301%2F03301b31-8cf4-48bb-afc7-38dab11e32c5%2Fktsljqb_processed.png&w=3840&q=75)
Transcribed Image Text:The wall of a room is made of plywood that has a thickness of 3.00 cm and an area of
18.0 m?. The room temperature is maintained at 25.0 °C higher than outside
temperature. Ignore other heat loss mechanisms except by conduction.
Given that:
Thermal conductivity of plywood, kpływood = 0.0800 W m¯1 °C-'
(a)
Find the magnitude of the rate of heat loss through the wall.
(b)
Calculate the amount of heat loss through the wall in half a day.
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