Two constant forces act on an object of mass m - 4.30 kg object moving in the xy plane as shown in the figure below. Force F, is 26.5 N at 35.0°, and force F, is 48.0N at 150°. At time t-0, the object is at the origin and has velocity (3.50i + 2.15j) m/s. 150 35.0 (a) Express the two forces in unit-vector notation. F,- F, - (b) Find the total force exerted on the object. (c) Find the object's acceleration. m/s?

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Chapter1: Units, Trigonometry. And Vectors
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Two constant forces act on an object of mass m = 4.30 kg object moving in the xy plane as shown in the figure below. Force F, is 26.5 N at 35.0°, and force F, is 48.0 N at 150°. At time t = 0, the object is at the origin and has velocity (3.50î + 2.15j) m/s.
150°
35.0°
(a) Express the two forces in unit-vector notation.
F, -
N
(b) Find the total force exerted on the object.
N
(c) Find the object's acceleration.
m/s2
Now, consider the instant t = 3.00 s.
(d) Find the object's velocity.
m/s
(e) Find its position.
(f) Find its kinetic energy from V½mv2.
kJ
(g) Find its kinetic energy from 2mv,2 + EF · AF.
kJ
Transcribed Image Text:Two constant forces act on an object of mass m = 4.30 kg object moving in the xy plane as shown in the figure below. Force F, is 26.5 N at 35.0°, and force F, is 48.0 N at 150°. At time t = 0, the object is at the origin and has velocity (3.50î + 2.15j) m/s. 150° 35.0° (a) Express the two forces in unit-vector notation. F, - N (b) Find the total force exerted on the object. N (c) Find the object's acceleration. m/s2 Now, consider the instant t = 3.00 s. (d) Find the object's velocity. m/s (e) Find its position. (f) Find its kinetic energy from V½mv2. kJ (g) Find its kinetic energy from 2mv,2 + EF · AF. kJ
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