Use a ROM to implement a digital circuit that accepts a three-bit binarynumber A = a2a1a0 and outputs the (A^2 + A) . Please provide the size and content of the ROMalong with the connection diagram for address and data lines.
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Use a ROM to implement a digital circuit that accepts a three-bit binary
number A = a2a1a0 and outputs the (A^2 + A) . Please provide the size and content of the ROM
along with the connection diagram for address and data lines.
Step by step
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- 5. Write an assembly language program to convert an 8-bit binary data to BCD. The binary data is stored in 4200H. Store the hundred's digit in 4251H. store the ten's and unit's digits in 4250Hb) There are five binary or hexadecimal numbers and six decimal conversions. Draw a line to connect each binary/hexadecimal to decimal number. Binary/Hexadecimal Decimal 4E 78 11011010 157 10011101 167 A7 25 19 2183. Convert 14.578 (unsigned) to decimal with accuracy of 4 digits if rounding is necessary. 4. Convert 7654.76548 (unsigned) to hexadecimal. 5. Calculate 11010110-10110111 (unsigned) and express the result in decimal. 6. Extend the following binary numbers from a 4 bit wide integer with 4 bit fraction system into an 8 bit integer with an 8 bit fraction so the same value is represented. First, assume the numbers are signed binary numbers. a) 0110.0100 b) 1010.0001 c) 1100.1 d) e) f) Now repeat, assuming a, b, c are unsigned numbers.
- What is the hexadecimal value stored in Register A after the following assembler has executed? LDA #0x71 NOTA NOTA LDR B,#0x71 ADC A,B LDR B,#0xEB ADC A,B NOTA LDR B,#0xD5 ADC A,B LDR B,#0x53 SBC A,B LDR B,#0x19 SBC A,B LDR B,#0x5E SBC A,BConsider a 2-bit parallel adder with ripple carry. It uses two full adders. It adds A1A0 to B1B0. Draw the adder and show all connections. Assuming that this adder will only add vectors (A1A0B1B0) that have odd parity AND neither number is 00, what is the average delay of the adder given that the outputs are initially high till the correct output is produced? Assume that the delay of a full adder is 6nsec.1. Gray code to Binary converter: Gray code is one of the codes used in digital systems. It has the advantage over binary numbers that only one bit in the code word changes when going from one number to the next. (See Table 1). Design a combinational circuit with 4 inputs and 4 outputs that converts a four- bit gray code number into an equivalent four-bit Binary number. Use Karnaugh map technique for simplification. Use LogicWorks for pre-lab demonstrations. Select the library "7400dev.clf* in the Parts Palette and then select the XOR chip 74-86. This would give you a set of 4 XOR's as shown in Fig. 1, just like the hardware chip 74-86. You could use as many as needed from these XOR gates in your design. Get back to ALL LIBRARIES and select switches for the inputs and Binary Probes as indicators of the outputs. Verify your design in the pre-Lab. During the Lab construct the circuit and verify its operations.
- please solve it fast, + digitak logic designQ2: Answer three of the following branches: 1. Add (01110101)2 with (00110011)2 in Decimal, Binary Octal and Hexadecimal. 2. Find (5.5)10) ^3 in binary multiplication. 3. Divide (30.25)10 by (5.5)10 in binary division. 4. Subtract (00110011): from (01110101): using Normal, I's complement and 2' complement subtraction.A logic function is expressed by the equation = 0.1.8.9.4. Plot the the values on the K-map below Note: w is the msb (most significant bit) 3 x 10 0- - W X 1 00 01 Write the simplified Sum of Products (SOP) expression. Use yz WIM or "" for NOT; 11 10 for AND; "+" for OR (without the quotation marks.
- Q1) Do as required. a) Express decimal number (-123) in binary as an 8-bit sign-magnitude form. b) Add the BCD numbers: 10011000 + 10010111Design a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A BC D) respectively with A is the MSB, the output variables are organized as (W X Y Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. X= BCD'+B'D+B'C X= BC'D'+B'D+BC X= BC'D'+B'D+B'C X= BC'D'+BD+B'CComputing the following two numbers using signed 2’s complement form with 8 bits : (convert the two operands to a binary format) +75 -52 ------ will generate a summation of: a. 00110011 b. 00010011 c. 00010111 d. 10010011