Use the Rossman Chance applet to find the regression equation.Xy40.877.163.5 40.364.1 69.648.4 81.129.3 80.832.6 93.660.6 56.636.9 82.656.5 79.144.1 74.357,9 49.180.1 17.152.1 38.651.1 46.652.9 76.954.2 59.968.1 12.861.3. 55.442.966.351.846.8What is the predicted explanatory value that will give you a value of 35.7 on the response variable? Reportanswer accurate to one decimal place.X=

The question is about regression.Given :To find :1 ) Regression equation using Rossman Chance…

Answered: Use the Rossman Chance applet to find…

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter13: Probability And Calculus

Section13.CR: Chapter 13 Review

Problem 9CR

See similar textbooks

Similar questions

EXERCISES The following table gives the life expectancy at birth of females born in the United States in various years from 1970 to 2010. Source: National Center for Health Statistics. Year of Birth Life Expectancy years 1970 74.7 1975 76.6 1980 77.4 1985 78.2 1990 78.8 1995 78.9 2000 79.3 2005 79.9 2010 81.0 Find the life expectancy predicted by your regression equation for each year in the table, and subtract it from the actual value in the second column. This gives you a table of residuals. Plot your residuals as points on a graph.
1. Find the regression equation. 2. Estimate the mental ability of an individual from the same population who has an SES rating 9.0
Find the regression equation, letting the first variable be the predictor (x) variable. Find the best predicted Nobel Laureate rate for a country that has 78.5Internet users per 100 people. How does it compare to the country's actual Nobel Laureate rate of 1.1 per 10 million people? Internet Users Per 100 Nobel Laureates80.3 5.679.6 24.277.3 8.644.6 0.183 6.138.3 0.190.1 25.189.1 7.680.1 8.983.3 12.753.2 1.976.6 12.756.8 3.379.5 1.591.5 11.493.7 25.465.1 3.157.8 1.967.9 1.794.3 31.785.3 31.387.7 1977.7 10.8
Run a regression analysis on the following bivariate set of data with y as the response variable. x y 59.4 32.5 51.8 -88.9 114.7 180 67 16.7 81.1 86.7 49.3 -3.4 90.6 106.3 35.2 -22.3 52.4 -8.3 40.2 -21.7 65 69.7 66.1 41.4 65.3 -28.9 100.3 151.8 67.2 -12.1 87.4 69.9 73.7 86.4 68.8 63.3 58.5 24.8 66.6 25.6 Verify that the correlation is significant at an α=0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of -74.3 on the response variable.What is the predicted explanatory value?x = (Report answer accurate to one decimal place.)
Run a regression analysis on the following bivariate set of data with y as the response variable. x y 67.9 -8.6 77.9 28.6 52.6 -25.5 52.9 -16.8 70.6 -5.8 101.5 136.4 55.9 -4.9 53.6 1.9 55.6 -20.4 71.3 41.8 77 15.5 96.1 104.8 Predict what value (on average) for the response variable will be obtained from a value of 82 as the explanatory variable.What is the predicted response value?
Run a regression analysis on the following bivariate set of data with y as the response variable. 67.7 -25.7 72.2 -5 55.8 21.3 64.1 11 70.9 64.9 61.6 -25 65.3 84.6 73.1 15 65 28.7 56.1 75.3 55.7 84.4 71 92 72.4 -5.4 72.4 16.5 64.1 38.7 48.6 96.5 70.8 -15.7 Predict what value (on average) for the response variable will be obtained from a value of 63.4 as the explanatory variable. Use a significance level of a 0.05 to assess the strength of the linear correlation. What is the predicted response value? y = (Report answer accurate to one decimal place.)
Run a regression analysis on the following data set with y as the response variable. y 67 | 37.6 69.9 37.4 54.9 33.5 55.7 36.1 77.9 40.2 77.2 39.2 69.4 38.9 71.3 40.1 72.1 37 What is the predicted value of the response variable when x = 62.1? Round to 1 decimal cs Scanned with CamScanner. place.
Run a regression analysis on the following bivariate set of data with y as the response variable. x y 62.5 74.4 78.5 -36.8 66.5 -29.7 47.5 89.8 76.3 3.5 12.1 219.3 41 121.9 81.8 45.5 39.8 143.3 45.7 147.1 62.5 12.8 53.1 90.3 67.9 9.8 58.8 61.5 84.2 7.8 25.7 192.2 59.3 -25.8 80.1 -22.4 Predict what value (on average) for the response variable will be obtained from a value of 30.3 as the explanatory variable. Use a significance level of α=0.05α=0.05 to assess the strength of the linear correlation.What is the predicted response value?y = (Report answer accurate to one decimal place.)
Run a regression analysis on the following bivariate set of data with y as the response variable. y 56.3 -257.6 14.5 670.8 49.4 431 60.7 200.3 60.1 70.3 52.6 -162.4 46.2 -406.9 45.1 -3.6 39.6 292.4 51.2 274.8 53.1 -77.4 50 496.6 46.9 251.5 48.5 -188.7 79.8 233 33.5 -415.6 49.2 431.3 download link provided here: Download CSV Predict what value (on average) for the response variable will be obtained from a value of 32.1 as the explanatory variable. Use a significance level of a = 0.05 to assess the strength of the linear correlation. What is the predicted response value? y = 169.94127 (Report answer accurate to one decimal place.)
A simple regression model for 10 pair of data resulted in a standard error of 3.95 (i.e., Se = 3.95), and the. The sum of squares of error (SSE) is ______. a. 187.23 b. 171.63 c. 156.03 d. 140.42 e. 124.82

Recommended textbooks for you

Calculus For The Life Sciences

Calculus

ISBN:

9780321964038

Author:

GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:

Pearson Addison Wesley,

Glencoe Algebra 1, Student Edition, 9780079039897…

Algebra

ISBN:

9780079039897

Author:

Carter

Publisher:

McGraw Hill

Calculus For The Life Sciences

Calculus

ISBN:

9780321964038

Author:

GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:

Pearson Addison Wesley,

Glencoe Algebra 1, Student Edition, 9780079039897…

Algebra

ISBN:

9780079039897

Author:

Carter

Publisher:

McGraw Hill

SEE MORE TEXTBOOKS