What is the volume ratio (Vf/Vi) required if the entropy of a gas (2mol) is to be increased by 50% at 298.15K. (R=8.314Jmol^(-1)K^(-1)) ? a. (Vf/Vi) = 2.47 b. (Vf/Vi) = 1.83 c. (Vf/Vi) = 1.88 d. (Vf/Vi) = 1.03
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What is the volume ratio (Vf/Vi) required if the entropy of a gas (2mol) is to be increased by 50% at 298.15K. (R=8.314Jmol^(-1)K^(-1)) ?
a. (Vf/Vi) = 2.47
b. (Vf/Vi) = 1.83
c. (Vf/Vi) = 1.88
d. (Vf/Vi) = 1.03
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- Suppose you have an endothermic reaction with H = + 15 kJ and a S of 150 J/K. Calculate G and Keq at 10, 100, and 1000 K.Which of the following statements must be true for the entropy of a pure solid to be zero? (i) The temperature of the solid must be 0 K. (ii) The solid must be crystalline, not amorphous. (iii) The solid must be perfectly ordered. (iv) The solid must be an element. Multiple Choice All four of i, ii, iii, and iv must be true Only i and ii must be true Only ii and iii must be true Only i and iii must be true Only i, ii, and iii must be trueUse the database on the textbook to calculate the entropy change of the following reaction under standard condition 1bar and 298 K: 2C2H6 (g) + 7O2 (g) = 4CO2 (g)+ 6H2O (L) ΔreactionS = _________ J/K/ (mol reaction). 4 sig. fig. per mole of reaction, not per mole of any subject. The data is copied from the appendix here material standard entropy ( J/K/mol) C2H6 229.60 O2 205.138 CO2 213.74 H2O(L) 69.91
- Consider the reaction co(g) + H20(1)– CO2(g) + H2(g) for which AH° = 2.800 kJ and AS° = 76.80 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 2.382 moles of C0(g) react under standard conditions at 298.15 K. AS universe |J/K (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored choose 'reactant favored'.Consider the reaction 4NH3(g) +50₂(g) 4NO(g) + 6H₂O(g) for which AH = -905.2 k) and AS 180.5 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 1.639 moles of NH3(g) react under standard conditions at 298.15 K. ASuniverse yk (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored, choose 'reactant favored'.15. When a solute is able to go spontaneously into solution: (A) both the enthalpy (AHsoln) and the entropy (ASsoln) of mixing are always positive. (B) both the enthalpy (AHsoln) and the entropy (ASsoln) of mixing are always negative. (C) the enthalpy (AHsoln) is always negative, while the entropy (Scoln) is always positive. (D) the enthalpy (AHsoln) may be positive or negative, but the entropy (ASsoln) is always positive. (E) the enthalpy (AHsoln) is always negative, but the entropy (ASsoln) may be positive or negative.
- A box contains a gas composed of 12 atoms each corresponding to the different stable isotopes of Tin (Sn). Initially, there are 10 atoms in the right compartment and 2 in the left compartment. After a certain amount of time passes, the system attains equilibrium with 6 atoms on each compartment. What is the change in entropy of the system? Use the constant KB= 1.3 x 10-23 [J/K*Molecule] in the solutionCalculate the value of ?p for the equation C(s)+CO2(g)↽−−⇀2CO(g)?p=? given that at a certain temperature C(s)+2H2O(g) H2(g)+CO2(g) ↽−−⇀CO2(g)+2H2(g)↽−−⇀H2O(g)+CO(g) ?p=? ?p1=3.07 Kp2=0.6713.(10p) The molar volume of a certain solid is 142.0 cm3mol-1 at 1.00 atm and 427.15 K, its melting temperature. The molar volume of the liquid at this temperature and pressure is 152.6 cm3mol-1. At 1.2 MPa, the melting. temperature changes to 429.26K. Calculate the enthalpy and entropy of fusion of the solid using the Clapeyron equation.
- Consider the reaction2NaOH(aq) + H2(g)2Na(s) + 2H2O(l)for which H° = 368.6 kJ and S° = 15.30 J/K at 298.15 K.(1) Calculate the entropy change of the UNIVERSE when 2.371 moles of NaOH(aq) react under standard conditions at 298.15 K. Suniverse = J/K (2) Is this reaction reactant or product favored under standard conditions?(3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored, choose 'reactant favored'.0 not enough information AS 0 not enough information AS < 0 AS = 0 17 AS 0 not enough information ●●● €Octane is typical of the components of gasoline. Estimate (a) the entropy of vaporization of octane, which boils at 126 °C at 1 atm. Entropy (a) = ________ J/K/mol. 3 sig. figures. Octane is typical of the components of gasoline. Estimate (b) the enthalpy of vaporization of octane, which boils at 126 °C at 1 atm. Enthalpy (b) = _______ kJ/mol. 3 sig. figures