(a) Calculate the angular momentum of the Moon due to its orbital motion about Earth. In your calculation use 3.84 x 108 m asthe average Earth-Moon distance and 2.36 × 106 s as the period of the Moon in its orbit. (Use 7.36 x 1022 kg for the mass of themoon.)2.89*10**3kg-m²/s(b) If the angular momentum of the moon obeys Bohr's quantization rule (L = nh) determine the value of the quantum number,n.2.74*10**6(c) By what fraction would the Earth-Moon radius have to be increased to increase the quantum number by 1?2xYour response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.Need Help?Read It

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Answered: (a) Calculate the angular momentum of…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter11: Gravity, Planetary Orbits, And The Hydrogen Atom

Section: Chapter Questions

Problem 39P

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If the speed of electron in the first Bohr orbit of radius 0.5 A is 2.24 × 106 m/s, then the period of revolution of the electron in this orbit is, (a) 1.403 × 10-16 S (b) 2.403 x 10-16 S (c) 1.403 × 10-¹1 S (d) 2.403 x 10-¹¹ S
(a) Calculate the angular momentum of the Moon due to its orbital motion about Earth. In your calculation use 3.84 × 108 m as the average Earth- Moon distance and 2.36 × 106 s as the period of the Moon in its orbit. (Use 7.36 × 1022 kg for the mass of the moon.) kg. m²/s 2.889e34 (b) If the angular momentum of the moon obeys Bohr's quantization rule (L: nh) determine the value of the quantum number, n. 2.7395e68 (c) By what fraction would the Earth-Moon radius have to be increased to increase the quantum number by 1? 1.825e-69 X Your response differs from the correct answer by more than 10%. Double check your calculations.
(a) Calculate the angular momentum of the Moon due to its orbital motion about Earth. In your calculation use 3.84 x 10⁰ m as the average Earth- Moon distance and 2.36 × 106 s as the period of the Moon in its orbit. (Use 7.36 × 1022 kg for the mass of the moon.) 2.889e34 kg. m²/s (b) If the angular momentum of the moon obeys Bohr's quantization rule (L = nħ) determine the value of the quantum number, n. 8.463e67 Your response differs from the correct answer by more than 10%. Double check your calculations. (c) By what fraction would the Earth-Moon radius have to be increased to increase the quantum number by 1? 2.3632e-6 X Your response differs from the correct answer by more than 100%.
(a) In the Bohr model of the atom, the ground-state electron in hydrogen has an orbital speed of 2190 km/s. What is its kinetic energy? (b) If you drop a 1.0-kg weight (about 2 lb) from a height of 1.0 m, how many joules of kinetic energy will it have when it reaches the ground? (c) Is it reasonable that a 30-kg child could run fast enough to have 100 J of kinetic energy?
A spherical shell has the surface density p and its radius is R, The gravitational force between this shell and a small sphere of mass 0.25Kg locoted at the distance of rfrom the centre of shell is given by GTRP O GRR?/3 O GIRP O None from these answers.
Solar energy reached the earth at the rate of about 14000 W/m^2 of surface perpendicular to the direction of the sun. By how much does the mass of the sun decreases in each second? The mean radian of the earth's orbit is 1.5 x10^11m. The surface area of a sphere= 4πr²
An electron in the n = 1 energy orbital of the hydrogen atom has an angular momentum of magnitude 1.055 x 10-34 J.s and an orbital radius of 5.292 x 10-11 m. The electron's mass is 9.11 x 10-31 kg. What is the electron's speed v in this orbital? m/s
A satellite of mass m, originally on the surface of the Earth, is placed into Earth orbit at an altitude h. a) Assuming a circular orbit, how long does the satellite take to complete one orbit? b) What is the satellite's speed? c) What is the minimum energy input necessary to place this satellite in orbit? Ignore air resistance but include the effect of the planet's daily rotation. Represent the mass and radius of the 3/2 2.7(R_ +h] GM Earth as Mg and Rg, respectively. (a: T= • b: c: leaving unstated) GM R+h
The mass of an electron is 9.11 x 10 ^-31 kg. The mass of a proton is 1.67 x 10 ^-27 kg. They are about 5.3×10^ −11 m apart in a hydrogen atom. What is the gravitational force between these two particles in the hydrogenatom?
If the angular momentum of an electron atom of hydrogen is equal to 34- ^ 10 × 3.15 j.s, in what orbit is this electron located? And what is his energy.
The answer key to this problem is stated as follows: x(t) = (4.0 cm)cos[(2π/8.0 s)t - π/3.0] Did they get the answer wrong? How you solved the problem landed with 'pi/6' In the answer key, it is with 'pi/3). Can you please explain?
The velocity of electron in the first Bohr orbit of radius 0.5 A.U. is 2.24 x 106 m/s. Calculate the period of revolution of the electron in the same orbit.

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