Dictionaries (100): Write a dictionary such that the following line of code holds or justify why this dictionary is not possible. In other words, what is dct? >>> dct['octopus'][(3,1,4)][True] ['Fish', 'Ocean'] (Check by plugging into python tutor)
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- ### Q5: Reduce No Change Python def reduce_no_change(fn, lst, base): """Same as Q4. However, preserve the lst in this problem. Object can be any python type which the input Not Allowed To Import Libraries Args: fn (function): Combination function which takes in two arguments and return an value with the same type as the second argument lst (List): A list of any type base (Object): A value of custom type which fn can handle. Returns: Object: A value after applying fn on lst. >>> reducer = lambda x, y: x + y >>> lst = [1, 2, 3] >>> a = reduce_lst(reducer, lst, 0) >>> a # a = reducer(reducer(reducer(base, lst[0]), lst[1]), lst[2]) 6 >>> lst >>> [1, 2, 3] # we preserve the list """ ### Modify your code here ### Modify your code herePython coding question: still in the process of learning dictionaries. How do you calculate the max/ average values of a dictionary when it has multiple values? So far I learned how to code a dictionary with a single value, key value. But when presented a problem for example. spent_dict = {'Gary_spent': [80,45, 60], 'Martha_spent': [53, 25, 70],'Jake_spent': [111, 95, 80]} How would I go about coding the total each person spent with multiple values for each key?Count word dominators def count_word_dominators(words): If you already solved the earlier count_dominators problem, you might notice that even though the problem was originally stated for lists of integers, the logic of domination did not depend on this fact in any way. As long as the individual elements can be compared with each other for order, the Pythonic spirit of duck typing allows the very same count_dominators function to handle a list of strings just as smoothly as it would handle a list of integers! For example, the function call count_dominators(['dog','emu','cat','bee']) would return 3, since 'emu', 'cat'and 'bee' dominate all words coming after them in the list when using the lexicographic order comparison. If your count_dominators function does not already pass this hurdle, try to rewrite it to contain no baked-in assumptions about elements being specifically integers. However, things become more interesting if we define domination between words of equal length with a…
- python: def traditions_dict(adict): """ Question 6 Given a dictionary that maps a person to a list of their favorite traditions, return a dictionary with the value being the list sorted by the last letter of each tradition. If two traditions have the same last letter, sort by the first letter. HINT: This will require the use of lambda functions Args: adict (dict) Returns: dict >>> traditions_dict({"Jacob": ["The Horse", "Stealing the t", "Midnight Bud"], "Athena": ["Mini Five-Hundred", "Freshman Cake Race", "Buzzweiser Song"], "Liv": ["Freshman Cake Race", "George P. Burdell", "Buzzweiser Song"]}) {'Jacob': ['Midnight Bud', 'The Horse', 'Stealing the t'], 'Athena': ['Mini Five-Hundred', 'Freshman Cake Race', 'Buzzweiser Song'], 'Liv': ['Freshman Cake Race', 'Buzzweiser Song', 'George P. Burdell']} >>> traditions_dict({"Madison": ["The Horse", "Midnight Bud", "Buzzweiser…Python Programming. Debug this program: ingredients = ['pears', 'apples', 'carrots', 'beets'] amounts = [6, 10, 1, 3] recipe_dictionary = {} # This dictionary will store ingredient/amount combinations. # There is a mistake in this part of the code. for i in range(len(ingredients)): recipe_dictionary[i] = (ingredients[i], amounts[i]) # These lines cause an error. If the code above is fixed, these lines will work! ingredients_to_look_up = input("Enter ingredient's name to look up: ") print(recipe_dictionary[ingredients])***python only*** Write a function votes_by_race() which takes a list of dicts as a parameter and returns a dict. For example, given the following list: votes = [{'for': 'A, 'age': 35, 'race': 'w'}, {'for': 'B', 'age': 40, 'race': 'b'}, {'for': 'B', 'age': 20, 'race': 'b'}, {'for': 'A', 'age': 30, 'race': 'a'}, {'for': 'A', 'age': 41, 'race': 'w'}, ] The call votes_by_race(votes) should return the following dict:{"White": 2, 'Black': 2, 'Asian': 1, "Hispanic': 0}
- ### Q7: Set to Numbers def create_n_to_tuple(): """Tuple to Integer In set theory, we can represent natural numbers recursively initially with empty sets. https://en.wikipedia.org/wiki/Set-theoretic_definition_of_natural_numbers We will use tuple in place of set to implement this representation. you will define two functions n_to_tuple and tuple_to_n, and return two function. The functions' specification is: n_to_tuple Args: n (int): an integer. Returns: t (tuple): tuple representation of the integer. None if integer cannot be represented. tuple_to_n Args: t (tuple): tuple representation of the integer Returns: n: integer which t represents -1 if tuple is invalid. # We will implement a time test on this function. >> n_to_tuple, tuple_to_n = create_n_to_tuple() >> n_to_tuple(0) () >> n_to_tuple(1) ((),) >> n_to_tuple(2) ((), ((),)) >>> r = n_to_tuple(-1) >>> print(r) None >> tuple_to_n(((), (),), (),)), ((), (),)))) # invalid -1 ### Modify your code here return ### Modify your code heredf.Month.replace(({1:'January', 2:'February', 3:'March',4:'April', 5:'May', 6:'June', 7:'July', 8:'August',9:'September',10:'October',11:'November',12:'December'}), inplace=True)df kindly explain what this code do in phytonC++ PROGRAMMINGTopic: HashTable - PolyHash Quadratic Explain the c++ code below.: SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed). You can also explain line by line for an upvote, thanks. EXPLAIN THE CODE BELOW: #include <cstdlib> #include <math.h> #include <cstring> #include <iostream> using namespace std; class HashTable { string* table; int N; int count; // TODO: Polynomial Hash Code using a=7 int hash_code(string key) { int code; int hash = 0; for (int i = 0; i < key.size(); i++) { char ch = key[i]; code += ((ch - 96) * pow(7, key.size() - (i + 1))); } return code; } // TODO: This hash table uses a MAD compression function // where a = 11, b = 461, p = 919 int compress(int code) { return (((11*code)+461) % 919) % N; }…
- please code in python Forbidden concepts: arrays/lists (data structures), recursion, custom classes You have been asked to take a small icon that appears on the screen of a smart telephone and scale it up so it looks bigger on a regular computer screen.The icon will be encoded as characters (x and *) in a 3 x 3 grid as follows: (refer image1 ) Write a program that accepts a positive integer scaling factor and outputs the scaled icon. A scaling factor of k means that each character is replaced by a k X k grid consisting only of that character. Input Specification:The input will be an integer such that 0 < k ≤ 10. Output Specification:The output will be 3k lines, which represent each individual line scaled by a factor of k and repeated k times. A line is scaled by a factor of k by replacing each character in the line with k copies of the character. [refer image2]Q6: Write a complete program in C++ that declares a one-dimensional array of integers. First, you have to read and print the array elements then you have to find and print the number of positive numbers and the number of negative numbers. (10 Marks)javascript only: Write a function `popularLetters(string)` that takes a string as an argument and returns an array of all of the characters that appear five or more times in the string. Examples: console.log(popularLetters('apple')); // [] console.log(popularLetters('bananas in pajamas')); // [ 'a' ] console.log(popularLetters('Yes, we have no bananas, we have no bananas today!')); // [ 'e', ' ', 'a', 'n' ]