Problem 3 The periodic current waveform in Figure (a) is applied to the circuit in Figure (b). Determine ao, an, bn, and vo(t). A 3 i 2 (a) 1 Answers: ao = bn = 2 3 (b) 19 202 3H an= Vo(t) =
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- A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating of 600 WVDC. The capacitor and resistor are connected to a 480-V, 60-Hz circuit. Is the voltage rating of the capacitor sufficient for this connection?For the waveform of Figure, determinea) Period I got 100us b) Frequency I got 10kHz c) Peak-to-peak value I got 150VThe peak distance of a sinusoidal waveform displayed on a C.R.O. screen is 6 cm and the 'volts/cm' switch is on 33 V/cm. The peak to peak voltage is given by O 396.00 V O 5.50 V O 139.99 V O 99.00 V
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- The R.M.S. value of a half-wave rectified current is 10A, its value for full-wave rectification would be amperes (a) 20 (b) 14.14 (c) 20/z (d) 40/zCalibri (Body) -11 by AaBbCcDx AaBbCcD AaBbC AaBbCc AaB AaBbCc. mat Painter BIU 1Normal 1No Spaci. Heading 1 Heading 2 Title Subtitle Chang Styles d Font Paragraph Styles IMPEDANCE QUIZ # 2 1. What capacitance when connected in series with a 500Q resistor will limit the current drawn from a 48-mV 465-kHz source to 20µA? * a. 144pF b. 145pF c. 146pF d. 147pF MY ANSWER: c.146pF 2. What is the total impedance at 20kHz of a series circuit consisting of a 1.5mH inductance, a 100Q resistance, and a 0.08uF capacitance? * a. 1340 41.7 b. 1930 L-37.2" C. 920 290 d. 530 2-12.6°this is electric circuit questin ...plz solve it early .plz solve early
- Convert the circuit from a T to a pi configurationThe peak to peak distance of a sinusoidal waveform displayed on a C.R.O. screen is 9 cm and the 'volts/cm' switch is on 25 V/cm. The peak voltage is given by O 2.78 V O 159.07 V O 112.50 V O 225.00 VA pure sinusoidal current is being rectified. For the given maximum value of half wave rectified current is 50 A, then the rms value of full wave rectification will be 50 (a) 100 (b) - - (c) 100 A (d) 70.7 A