Answered: Multiple crosses were made between…

Name: Multiple crosses were made between true-breeding lines of black and ye
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Description: Multiple crosses were made between true-breeding lines of black and yellow Labrador retrievers. All the F1 progeny were yellow. When these progeny were intercrossed, they produced an F2 consisting of 121 yellow, 9 black and 30 chocolate. What epistat

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter15: Genomes And Genomics

Section: Chapter Questions

Problem 1QP: The gene controlling ABO blood type and the gene underlying nail-patella syndrome are said to show...

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Multiple crosses were made between true-breeding lines of black and yellow Labrador retrievers. All the F1 progeny were yellow. When these progeny were intercrossed, they produced an F2 consisting of 121 yellow, 9 black and 30 chocolate.

What epistatic ratio and what kind of epistasis is approximated in the F2?

Propose a biochemical pathway for coat color in Labrador retrievers based on the type of epistasis.

Correlate each genotype with the phenotype that would occur in your pathway. Also show the frequency of each genotype.

A-B-

A-bb aaB- aabb

Expert Solution

Introduction:-

Black $\times$ Yellow $\to$ All Yellow (F₁)
F₁ $\times$ F_{2 $\to$}121 Yellow $+$ 9 Black $+$ 30 Chocolate
Total offspring in F₂ $=$ (121 $+$ 9 $+$ 30) $=$ 160

Corresponding Ratios:-

Yellow $=$ $\frac{121}{160}$ $\approx$ 0.76

Black $=$ $\frac{9}{160}$ $\approx$ 0.06

Chocolate $=$ $\frac{30}{160}$ $\approx$ 0.19

Now, Dividing each by frequency of lowest phenotype, i.e. Black $=$ 0.06 we get:-

Yellow $=$ $\frac{0.76}{0.06}$ $=$ 12.6 $\approx$ 12

Black $=$ $\frac{0.06}{0.06}$ $=$ 1 $\approx$ 1

Chocolate $=$ $\frac{0.19}{0.06}$ $=$ 3.16 $\approx$ 3

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