I’m trying to construct an ANOVA table with my data , but the SSregr, SStotal, and SSerror are coming out negative. Are these correct, or am I doing something wrong? y = 60.7 +15.75X-constructed graph in excel+ SSErrorSS TOTAL = SSRegrS SERROR = 2 (Y₁-Y ) ²iHAY=114.25Biting force (Y) (121.6-114.257)³² = 54.02(111. 6-114.25)² = 7.02(96.7 - 114.25)² = 308.00(106.5-114.25) = 60.06( 129.0-114.25)² = 217.56(101.9-114.25)<= 152.52(134.4-114.25)² = 406.02(111.3-114.25)² = 8.70Residuel S SERROT & (Y₁-7)² = 1213.90Source of emerRegression✓ Error✓TotalANOVASSDFMSE (MS) FSSRegr1MSRegr +BsSx MsregS SError 1-2 MSError 0SS TOTALn-12SS TOTAL = EY² - (EY)² - 719436-( 913n8=-24760.13C.V.SeeMSError Table= SS EmerS STOTAL S Spear-24760113-1213.90 = -25974.03= SSError (x) headwidth | X²4.313.922.56Total:3.724.212.954.742.8427.1918.5715,366.5513.8317.728.7022.478.07111.271.18((P) Biting Force/Y ²121.6111.696.7106.512.9.0101.9134.4113.3913XY14786.5524.1012454.6 437.479350.9247.5511342.3396.1816641543.0910383.6 300.60518063.4635.06123877316.092794.363400.15

The data on head width(X) and biting force(Y) is given below sr no Head width(X)Biting…

(X) headwidth X² 4.31 3.92 2.56 Total: 3.72 4.21 2.95 4.74 2.84 27.19 18.57 15,36 6.55 13.83 17.72 8.70 22.47 8.07 111.27 (1) Biting Force / Y 2 121.6 111.6 96.7 106.5 129.0 101.9 134.4 113.3 913 14786.5 XY 524.10 12454.6 437.47 9350.9 247.55 11342.3 396.18 543,09 300.605 635.06 316.092 3400.15 16641 10383.6 18063.4 123877 794.36

(X) headwidth X² 4.31 3.92 2.56 Total: 3.72 4.21 2.95 4.74 2.84 27.19 18.57 15,36 6.55 13.83 17.72 8.70 22.47 8.07 111.27 (1) Biting Force / Y 2 121.6 111.6 96.7 106.5 129.0 101.9 134.4 113.3 913 14786.5 XY 524.10 12454.6 437.47 9350.9 247.55 11342.3 396.18 543,09 300.605 635.06 316.092 3400.15 16641 10383.6 18063.4 123877 794.36

Mathematics For Machine Technology

8th Edition

ISBN:9781337798310

Author:Peterson, John.

Publisher:Peterson, John.

Chapter25: Achievement Review—section Two

Section: Chapter Questions

Problem 3AR: Express these ratios in lowest fractional form. 3. 12:46

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